1.) Engineers want to design seats in a commercial aircraft so that they are wide enough to fit 95% of all males. Men have hip breadths that are normally distributed with a mean of 14.7 and a standard deviation of .9. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%.

The hip breadth for men that separates the smallest 95% from the largest 5% is P95 ___ inches

The hip breadth for men that separates the smallest 95% from the largest 5% is P95 ___ inches

2.) Determine whether the given procedure results in a binomial distribution. If it is not binomial identify the requirements that are not satisfied randomly selecting 20 students in recording how much they like rap music on a scale from 1 to 10 .

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.5 in. And a standard deviation of 0.8 in. Find P99. That is, find the hip breadth for men that separates that smallest 99% from the hip breadth for men that separates the smallest 99% from the largest 1%

The hip breadth for men that separates the smallest 99% from the largest 1% is P 99 is ? Inches

Engineers want to design seats in commercial aircraft so that they are wide enough to fit

90%

of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of

14.1

in. and a standard deviation of

0.8

in. Find

P90.

That is, find the hip breadth for men that separates the smallest

90%

from the largest

10%.

The hip breadth for men that separates the smallest

90%

from the largest

10%

is

P90=[ ]

in.

Engineers want to design seats in commercial aircraft so that they are wide enough to fit

99%

of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of

14.1

in. and a standard deviation of

0.8

in. Find

P99.

That is, find the hip breadth for men that separates the smallest

99%

from the largest

1%.

**from the largest**

**is**

**in.**

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.9 in. and a standard deviation of 0.9 in. Find P95. That is, find the

hip breadth for men that separates the smallest 95% from the largest 5%.

The hip breadth for men that separates the smallest 95% from the largest 5% is P95 =

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4in. and a standard deviation of 1.1 in. Find P95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%.

The hip breadth for men that separates the smallest 95%from the largest 5% is P95= _____inches

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90%of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of

14.7in. and a standard deviation of 1.2in. Find P90.

That is, find the hip breadth for men that separates the smallest

90% from the largest 10%.

The hip breadth for men that separates the smallest 90%from the largest

10% is P90=nothing in.

(Round to one decimal place as needed.)

Engineers want to design seats in a commercial aircraft so that they are wide enough to fit 95% of all males. (Accomodating 100% would require very wide seats that would be much too expensive). Men have hip breadths that are normally distributed with a mean of 14.1 in. and standard deviation of 0.8 in. Find p95. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%

The hip breadth for men that separates the smallest 95% from the largest 5% is p95

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