If the variable Z is normally distributed with mean equal to 0 and standard deviation equal to 1.
The probability that the variable takes a value less than -0.39 or greater than -0.13 is:
P(Z < -0.39 or Z > -0.13) = 0.1517
P(Z < -0.39 or Z > -0.13) = 0.10
P(Z < -0.39 or Z > -0.13) = 0.7966
P(Z < -0.39 or Z > -0.13) = 0.90
P(Z < -0.39 or Z > -0.13) = 0.0517
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