# Learning Objectives

In this lab we will:

• Use if-else statements to find the highest score amongst a group of 3 values
• Use data structures to retrieve the name that corresponds to the highest score (potentially, in a data structure that makes this easier)

## Main Idea

The problem presented in this lab is an active research area in Computer Science called differential privacy and secure (multi-party) computation. In this lab, we won’t be able to use a differentially private algorithm, so we will assume that the users stored their data secretly somewhere and cannot see each other’s values.

Three friends finished the test and want to secretly compare their test scores. They do not want to know each other’s exact score, but they do want to know who achieved the best results for this test.

## Instructions

1. Input the names and scores of the three friends one after another. (Check out the example input below)

2. Your program should store both names and scores. Think about types to store and structures to store (You can do it in many ways, but we suggest tuples or named tuples or just separate variables.

3. Compare the scores and find the highest.

3.1. If there is one best score – print the name of the friend that achieved that score.

3.2. If there are two friends with equal highest scores – print both names, separated by space, in the order of input.

3.3. If all three friends achieved equal scores – print all three names, separated by space, in the order of input.

# Examples

Input

Ann 10 Maria 9 Cindy 7

Output

Ann

Input

Ann 10 Maria 9 Cindy 10

Output

Ann Cindy

Input

Ann 10 Maria 10 Cindy 10

Output

Ann Maria Cindy

This is my wrong code below:

name1=input()

m1=int(input())

name2=input ()

m2=int(input ())

name3=input ()

m3=int(input ())
string = “”
if(m1>=m2) and (m1>=m3):

large=m1;

elif(m2>=m3) and (m2>=m1):

large=m2;

else:

large=m3;

if large == m1:
string ==string + m1
if large == m2:
string == string + m2
if large == m3:
string = string + m3
print(string)

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