10.1 | 9.2 | 10.9 | 9.5 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

Use a calculator with mean and sample standard deviation keys to find the sample mean reading and the sample standard deviation *s*. (in mg/dl; round your answers to two decimal places.)

= mg/dl*s* = mg/dl

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (in mg/dl; round your answer to two decimal places.)

lower limit mg/dl

upper limit mg/dl

Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency. No. This confidence interval suggests that the patient may still have a calcium deficiency.No. This confidence interval suggests that the patient no longer has a calcium deficiency.

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of *x* values has an approximately normal distribution.

9.30 | 9.60 | 10.30 | 8.90 | 9.40 | 9.80 | 10.00 | 9.90 | 11.20 | 12.10 |

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation *s*. (Round your answers to four decimal places.)

x= _________ mg/dl

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (Round your answer to two decimal places.)

lower limit _________ mg/dl

upper limit __________ mg/dl

(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

(1) Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

(2) Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

(3) No. This confidence interval suggests that the patient may still have a calcium deficiency.

(4) No. This confidence interval suggests that the patient no longer has a calcium deficiency.

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of *x* values has an approximately normal distribution.

9.7 | 8.6 | 10.1 | 9.1 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

Use a calculator with mean and sample standard deviation keys to find the sample mean reading and the sample standard deviation *s*. (in mg/dl; round your answers to two decimal places.)

x = mg/dl*s* = mg/dl

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (in mg/dl; round your answer to two decimal places.)

lower limit= mg/dl

upper limit = mg/dl

Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency

.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of *x* values has an approximately normal distribution.

9.70 | 9.00 | 10.50 | 8.90 | 9.40 | 9.80 | 10.00 | 9.90 | 11.20 | 12.10 |

(a)

Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation *s*. (Round your answers to four decimal places.)

x= mg/dl *s*= mg/dl

(b)

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (Round your answer to two decimal places.)

lower limit mg/dl upper limit mg/dl

(c)

Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency. No. This confidence interval suggests that the patient may still have a calcium deficiency.No. This confidence interval suggests that the patient no longer has a calcium deficiency.

Over the past several months, an adult patient has been treated for tetany (sever muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.

9.1 8.6 10.9 8.7 9.4 9.8 10.0 9.9 11.2 12.1

x = mg/dl

s = mg/dl

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood (in mg/dl; round your answer to two decimal places.)

lower limit mg/dl

upper limit mg/dl

(c) based on your results in part (b). do you think this patient still has a calcium deficienty? Explain.

*x* values has an approximately normal distribution.

9.9 | 9.0 | 10.1 | 8.9 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

x = _______ mg/dl*s* = _______ mg/dl

lower limit _______ mg/dl

upper limit _______mg/dl

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency.

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

*x* values has an approximately normal distribution.

9.5 | 9.4 | 10.5 | 8.9 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

Use a calculator with mean and sample standard deviation keys to find the sample mean reading and the sample standard deviation *s*. (in mg/dl; round your answers to two decimal places.)

= mg/dl *s* = mg/dl

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (in mg/dl; round your answer to two decimal places.)

lower limit mg/dl

upper limit mg/dl

over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of *x* values has an approximately normal distribution.

10.1 | 9.2 | 10.7 | 8.5 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

x_____= mg/dl *s_____* = mg/dl

lower limit _____ mg/dl

upper limit ______ mg/dl

a.) Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

b.) Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

c.) No. This confidence interval suggests that the patient may still have a calcium deficiency.

d.) No. This confidence interval suggests that the patient no longer has a calcium deficiency.

9.1 | 9.2 | 10.4 | 8.9 | 9.5 | 9.5 | 10.8 | 10.3 | 11.5 | 12.0 |

(a)

Find the sample mean reading x and the sample standard deviation *s*. (Round your answers to four decimal places.)

x= mg/dl*s*= mg/dl

(b)

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (Round your answer to two decimal places.)

lower limit mg/dlupper limit mg/dl

(c)

9.4 | 9.5 | 10.2 | 9.1 | 9.6 | 9.8 | 10.7 | 10.0 | 11.9 | 12.1 |

(a)

Find the sample mean reading x and the sample standard deviation *s*. (Round your answers to four decimal places.)

x= mg/dl*s*= mg/dl

(b)

Find a 99.4% confidence interval for the population mean of total calcium in this patient’s blood. (Round your answer to two decimal places.)

lower limit mg/dlupper limit mg/dl

(c)

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency.

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

*x* values has an approximately normal distribution.

9.9 | 8.8 | 10.9 | 9.5 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

Use a calculator with mean and sample standard deviation keys to find the sample mean reading and the sample standard deviation *s*. (in mg/dl; round your answers to two decimal places.)

= mg/dl*s* = mg/dl

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (in mg/dl; round your answer to two decimal places.)

lower limit mg/dl

upper limit mg/dl

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency.

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

*x* values has an approximately normal distribution.

9.5 | 9.4 | 10.5 | 8.9 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

*s*. (in mg/dl; round your answers to two decimal places.)

= mg/dl *s* = mg/dl

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient’s total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.

9.5 9.0 10.3 9.5 9.4 9.8 10.0 9.9 11.2 12.1

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x bar and the sample standard deviation s. (in mg/dl; round your answers to two decimal places.)

x bar = mg/dl

s = mg/dl

9.5 9.0 10.3 9.5 9.4 9.8 10.0 9.9 11.2 12.1

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x bar and the sample standard deviation s. (in mg/dl; round your answers to two decimal places.)

x bar = mg/dl

s = mg/dl

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (in mg/dl; round your answer to two decimal places.)

lower limit mg/dl

upper limit mg/dl

(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.

Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.

No. This confidence interval suggests that the patient may still have a calcium deficiency.

No. This confidence interval suggests that the patient no longer has a calcium deficiency.

9.50 | 8.60 | 10.30 | 8.70 | 9.40 | 9.80 | 10.00 | 9.90 | 11.20 | 12.10 |

(a)

Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation *s*. (Round your answers to four decimal places.)

x= mg/dl*s*= mg/dl

(b)

Find a 99.9% confidence interval for the population mean of total calcium in this patient’s blood. (Round your answer to two decimal places.)

lower limit mg/dlupper limit mg/dl

I am having a problem with part b of this question. Is it possible to be provided the excel steps to solve? If not, the manual steps with answer will still greatly help. Thanks in advance.

*x* values has an approximately normal distribution.

10.1 | 9.6 | 10.3 | 9.3 | 9.4 | 9.8 | 10.0 | 9.9 | 11.2 | 12.1 |

Use a calculator with mean and sample standard deviation keys to find the sample mean reading and the sample standard deviation *s*. (in mg/dl; round your answers to two decimal places.)

= 10.17 mg/dl*s* = .86 mg/dl

lower limit mg/dl

upper limit mg/dl

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