9.) The absorption peaks of chlorophyll a are at 665 nm and 465 nm. Assume that a plant can
convert all the photon energy it absorbs to food calories.
a.) Calculate the energy of one 665 nm photon and one 465 nm photon. Which wavelength would allow the plant to produce more energy (and more calories)?
I’ve completed part A and I got 2.99×10^-19 for 665nm and 4.27×10^-19 for 465nm. And I believe 465nm wavelength would allow the plant to produce more energy. I need help with part B
b.) Use the energy at this (more energetic) wavelength to calculate the number of calories a plant could make if it were perfectly efficient and absorbed 1 mole of photons at this wavelength. (1 calorie = 4.184 Joules, 1 Calorie = 4.184 KJ).
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