# Use a 0.05 significance level

Use a 0.05 significance level to test the claim that the different samples come from populations with the same mean. Use the traditional method.

List

• the null and alternative hypothesis,
• the critical value,
• the test statistic,
• Draw the graph and label the test statistic, critical value and rejection regions.

Reject or fail to reject?

State the conclusion as outlined in the template or book

Your hypothesis test must take up one whole page only (8 1/2″ x 11″), typed or written and must be neat.

 ANOVA Source of Variation SS df MS F P-value Factor 13.500 3 4.500 5.171 0.0011 Error 13.925 16 0.870 Total 27.425 19

# Use a 0.05 significance level

Use a 0.05 significance level to test the claim that the different samples come from populations with the same mean. Use the traditional method

• the null and alternative hypothesis,
• the critical value,
• the test statistic,
• Draw the graph and label the test statistic, critical value and rejection regions.

Reject or fail to reject?

State the conclusion as outlined in the template or book

 ANOVA Source of Variation SS df MS F P-value Factor 13.500 3 4.500 5.171 0.0011 Error 13.925 16 0.870 Total 27.425 19

# Use a 0.05 significance level

A random sample of 760 subjects was obtained, and each was tested for left-hand writing. Results are in the table below.

 Writes with Left Hand? Yes No Male 26 218 Female 64 452

Use a 0.05 significance level to test the claim that left-handedness is independent of gender.

Round to four decimal places if necessary.

a) Write the hypotheses.

b) The expected frequency of female who is left-handedness is

The expected frequency of male who is not left-handedness is

c) significance level: α =

d) Test statistic:

Clearly state whether test statistic in this claim is z, t, chisq. For example, “chisq=1.2345”

e) Compute p-value of the test statistic.

f)  Decision:   Type “yes” if reject null hypothesis. Type “no” if not to reject null hypothesis.

# Use a 0.05 significance level

Use a 0.05 significance level to test the claim that pedestrian fatalities are independent of the intoxication of the driver and the intoxication of the pedestrian. Use the traditional method. Include all the expected values in the chart.

• the null and alternative hypothesis,
• the critical value,
• the test statistic,
• Draw the graph and label the test statistic, critical value and rejection regions.

Reject or fail to reject?

State the conclusion as outlined in the template or book

 Pedestrian Intoxicated Expected Value Pedestrian not intoxicated Expected Value Totals Driver Intoxicated 59 79 Driver not Intoxicated 266 581 Totals

# Use a 0.05 significance level

Use a 0.05 significance level to test the claim that pedestrian fatalities are independent of the intoxication of the driver and the intoxication of the pedestrian. Use the traditional method. Be sure to include all the expected values in the chart.

 Pedestrian Intoxicated Expected Value Pedestrian not intoxicated Expected Value Totals Driver Intoxicated 59 79 Driver not Intoxicated 266 581 Totals

List

• the null and alternative hypothesis,
• the critical value,
• the test statistic,
• Draw the graph and label the test statistic, critical value and rejection regions.

Reject or fail to reject?

State the conclusion

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